11x^2-62x-275=0

Solution for 11x^2-62x-275=0 equation:

11x^2-62x-275=0

a = 11; b = -62; c = -275;
Δ = b2-4ac
Δ = -622-4·11·(-275)
Δ = 15944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15944}=\sqrt{4*3986}=\sqrt{4}*\sqrt{3986}=2\sqrt{3986}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-2\sqrt{3986}}{2*11}=\frac{62-2\sqrt{3986}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+2\sqrt{3986}}{2*11}=\frac{62+2\sqrt{3986}}{22}
$